Question

Let (-5, 2) be a point on the terminal side of 0.

Find the exact values of coso , csco, and tano.

Answer 1

Following are the response to this questions:

Explanation:

Please find the graph file in the attachment.

Given:

P=2

B=-5

H=?

`H=√(P^2+B^2)`

`=√(2^2+(-5)^2)\\\\=√(4+25)\\\\=√(29)\\\\`

Using formula:

`\to \ cosec \theta \ or\ \ csco \theta =(H)/(P)\\\\\to \cos \theta=(B)/(H)\\\\\to \tan \theta=(p)/(B)\\\\`

So,

`\to \ cosec \theta \ or\ \ csco \theta =(√(29))/(2)\\\\\to \cos \theta=(-5)/(√(29)) =(-5)/(√(29))* (√(29))/(√(29))=-(5√(29))/(29)\\\\\to \tan \theta=(2)/(-5)= -(2)/(5)\\\\`