Question

I need help answering number 14 A B and C. Thank you!

Answer 1

Step-by-step explanation:

TiO2 + C + 2 CI2 → TiCI4 + CO2

(a)

(2.16 mol TiO2) x (2 mol CI2 / 1 mol TiO2) x ( 70.9064 g C/mol) = 306 g CI2

(b)

(2.16 mol TIO2) x (1 mol C / 1 mol TiO2) x ( 12.01078 g C/mol)n= 25.9 g C

(c)

Use the law of conservation of mass:

(2.16 mol TiO2) x ( 79.8660 g TiO2/mol) + (306 g CI2 + 25.9 g C = 504 g total.

Hope this help!:)