Question

Plz help I'll give brainy!!!

Complete the missing parts of the
table for the following function.
y=(1/5)^x

X-2 -1 0 1 2 3

y [?] [ ] 1 1/5. 1/?
1/125

Answer 1

25 5 1/125

Explanation:

Answer 2

see below

Explanation:

we are given a exponential function

`\displaystyle y = \left(1/5\right) ^(x)`

we want to figure out the missing values of y for x i.e (-2,-1, and 2) to do we can consider substituting so,

when x is -2 y should be

`\displaystyle y = \left(1/5\right) ^( - 2)`

rewrite ⅕ in exponent notation:

`\displaystyle y = \left((5) ^( - 1) \right) ^( - 2)`

by law of exponent we obtain:

`\displaystyle y = (5) ^( 2)`

simplify square:

`\displaystyle y = \boxed{ 25}`

when x is -1:

`\displaystyle y = \left(1/5\right) ^( - 1)`

rewrite ⅕ in exponent notation:

`\displaystyle y = \left((5) ^( - 1) \right) ^( - 1)`

use law of exponent which yields:

`\displaystyle y = \boxed5`

when x is 3:

`\displaystyle y = \left(1/5\right) ^( 3)`

by law of exponent we obtain:

`\displaystyle y = 1/ {5}^(3)`

simplify square which yields:

`\displaystyle y = \frac{1}{ \boxed{125}}`