Explanation:
1/3(9k+12)=15
We move all terms to the left:
1/3(9k+12)-(15)=0
Domain of the equation: 3(9k+12)!=0
k∈R
We multiply all the terms by the denominator
-15*3(9k+12)+1=0
Wy multiply elements
-45k(9+1= 10
Answer:
21
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