Question

A,b,c are all positive integers

a:b=3:8 b:c=6:11
work out the smallest possible value of a+b+c

Answer 1

9514 1404 393

Answer:

77

Explanation:

We can use a number of ratio units to represent b that is the LCM of 8 and 6. That value is 24. Then multiplying the first ratio by 3 and the second by 4, we have ...

a:b = 9:24 and b:c = 24:44

Then the ratios of all are ...

a : b : c = 9 : 24 : 44

and the sum is 9+24+44 = 77.