Question

How far apart are two conducting plates that have an electric field strength of 8.53 x 103 V/m between them, if their potential difference is 23.0 kV

Answer 1

`d=2.7m`

Step-by-step explanation:

From the question we are told that:

Electric Field strength
`E=8.53 * 10^3 V/m`

Potential difference is
`V= 23.0 kV`

Generally the equation for distance is mathematically given by

`d=(V)/(E)`

`d=(23.0*10^3)/(8.53 * 10^3 V/m)`

`d=2.7m`