Question

A wheel accelerates from rest to 20 rad/s at a uniform rate of 3.5 rad/s2. Through what angle (in radians) did the wheel turn while accelerating

Answer 1

`\theta=57.14rad`

Step-by-step explanation:

From the question we are told that:

Angular Velocity
`\omega=20rad/s`

Acceleration
`a=3.5rads/s^2`

Generally the equation for Angular velocity is mathematically given by

`\omega_2^2=\omega_1^2+2 a \theta`

Therefore

`20^2=0+2*2.5*\theta`

`\theta=(400)/(2*3.5)`

`\theta=57.14rad`