Question

CANNNN SOMEONEEEEE HELPPPP MEEE OUTTTTT !!!!!

Answer 1

`\boxed{\sf sinX =(21)/(29)}`

Explanation:

We need to find out the value of sinX using the given triangle . Here we can see that the sides of the triangle are 21 , 29 and 20.

We know that the ratio of sine is perpendicular to hypontenuse .

`\sf\longrightarrow sin\theta =( perpendicular)/(hypontenuse)`

Here we can see that the side opposite to angle X is 21 , therefore the perpendicular of the triangle is 21. And the side opposite to 90° angle is 29 . So it's the hypontenuse . On using the ratio of sine ,

`\sf\longrightarrow sinX =( p)/(h)=(ZY)/(ZX)`

Substitute the respective values ,

`\sf\longrightarrow \boxed{\blue{\sf sin\ X =(21)/(29)}}`

Hence the required answer is 21/29 .

Answer 2

sin X = 21/ 29

Explanation:

Since this is a right triangle

sin X = opp side/ hypotenuse

sin X = 21/ 29