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Home sizes in Anytown, USA have a mean of 2400 square feet and a standard deviation of 450 square feet. What is the probability that a random sample of 50 homes in Anytown, USA has mean square footage less than 2200 square feet

User Prashanth B
by
2.8k points

1 Answer

16 votes
16 votes

Answer:

0.00084

Explanation:

We are given that

Mean,
\mu=2400 square feet

Standard deviation,
\sigma=450square feet

n=50

We have to find the probability that a random sample of 50 homes in Anytown, USA has mean square footage less than 2200 square feet.


P(x<2200)=P((x-\mu)/((\sigma)/(√(n)))<P((2200-2400)/((450)/(√(50))))


P(x<2200)=P(Z<(-200)/((450)/(√(50))))

Using the formula


z=(x-\mu)/((\sigma)/(√(n)))


P(x<2200)=P(Z<-3.14)


P(X<2200)=0.00084

Hence, the probability that a random sample of 50 homes in Anytown, USA has mean square footage less than 2200 square feet=0.00084

User Naveed Ahmad
by
2.7k points
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