Question

A 42 cm long solenoid, 1.8 cm in diameter, is to produce a 0.030 T magnetic field at its center. If the maximum current is 4.5 A, how many turns must the solenoid have?

Answer 1

The number of turns is
`2.2 * 10^(3)`

Step-by-step explanation:

The computation of the number of turns is shown below:

`B = \mu o (N)/(L)I \\\\N = (BL)/(\mu oI)\\\\= (0.030 T * 0.42)/(4\pi* 10^(-7) (4.5)) \\\\= 2.2 * 10^(3)`

hence, the number of turns is
`2.2 * 10^(3)`