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A football team score 81 points in a particular match, made up of a combination of g number of goals (worth 6 points) and b number of behinds (worth 1 point). If the team score three more goals than behinds, find the number of goals and number of behinds scored.

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Answer:

Number of goals is 12 and number of behinds is 9. 6×12=72 + 1×9=9 72+9=81

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