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2x^2+3x-7=0 2x^(2) + 3x - 7 = 0 ​
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13 votes
2x^2+3x-7=0

2x^(2) + 3x - 7 = 0
​

User MingalevME
by
8.6k points

1 Answer

11 votes

Answer:

x =
(-3\pm√(65) )/(4)

It is written like this in latex code: $\frac{-3\pm\sqrt{65}}{4}$

Explanation:

User Cremno
by
8.5k points
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