Question

Find the slope-intercept form of an equation of the line perpendicular to the graph of x – 3y = 5 and passing through (0, 6).

Answer 1

y=-3x+6

Explanation:

x-3y=5

y=1/3x-5/3

slope of perpendicular line is -3 (opposite reciprocals)

y=mx+b

x=0 and y=6

6=3x+b

6=3(0)+b

6=b

y=-3x+6