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Please help with this problem!!! ASAP!

Please help with this problem!!! ASAP!-example-1

1 Answer

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Answer:

2.94 × 10²⁴ molecules

Step-by-step explanation:

Step 1: Given data

Volume of acetone (V): 360 mL (360 cm³)

Density of acetone (ρ): 0.788 g/cm³

Step 2: Calculate the mass of acetone (m)

Density is equal to the mass of acetone divided its volume.

ρ = m/V

m = ρ × V

m = 0.788 g/cm³ × 360 cm³ = 284 g

Step 3: Calculate the moles corresponding to 284 g of acetone

The molar mass of acetone is 58.08 g/mol.

284 g × 1 mol/58.08 g = 4.89 mol

Step 4: Calculate the number of molecules in 4.89 moles of acetone

We will use Avogadro's number: there are 6.02 × 10²³ molecules of acetone in 1 mole of molecules of acetone.

4.89 mol × 6.02 × 10²³ molecules/1 mol = 2.94 × 10²⁴ molecules

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