Answer:
![= 3.105x10^(24)molecules\ acetone](https://img.qammunity.org/2022/formulas/chemistry/college/1q34iugj7v726lutswnoqzvcwalhsx9yyl.png)
Step-by-step explanation:
Hello!
In this case, given the volume of acetone, it is possible to compute the mass and next the moles via its molar mass (58.08 g/mol) as shown below:
![n_(acetone)=380mL*(0.788g)/(1mL) *(1mol)/(58.08 g) \\\\n_(acetone)=5.16mol](https://img.qammunity.org/2022/formulas/chemistry/college/2e1ovejyqeho2w28cg4t55xn19fidx4x75.png)
Then, via the Avogadro's number it is possible to compute the acetone molecules as follows:
![=5.16mol*(6.022x10^(23)molecules)/(1mol)\\\\= 3.105x10^(24)molecules\ acetone](https://img.qammunity.org/2022/formulas/chemistry/college/p4dknbq5gyddxji1t1a524xc26uw0e9ojq.png)
Best regards!