Question

What is the electric field strength between two parallel conducting plates separated by 10 cm and having a potential difference between them of 2000 V?

a.
2000 V/m

b.
200 V/m

c.
20 kV/m

d.
200000 V/m

Answer 1

• Potential Difference (V) = 2000 V

• Distance b/w the two parallel plates (d) = 10 cm = 10/100 = 1/10 = 0.1 m

• Electric field (E) = ?

`\implies V = E.d`

`\implies E = (V)/(d)`

`\implies E = (2000)/(0.1)`

`\implies E = \frac{2000}{ {10}^( - 1) }`

`\implies E = 2000 * {10}^(1)`

`\implies\bf E = 20000 \:V/m`

`\implies\bf E = 20\:kV/m`

Hence, option C) the correct answer.