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32 votes
Fine FG , given that line HF is perpendicular bisector or EG

Fine FG , given that line HF is perpendicular bisector or EG-example-1
User Yaniv De Ridder
by
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1 Answer

26 votes
26 votes

Answer:

FG = 7

Explanation:

We'll begin by calculating HF. This can be obtained by using the pythagoras theory as illustrated below:

EF = 7

EH = 3

HF =?

EF² = EH² + HF²

7² = 3² + HF²

49 = 9 + HF²

Collect like terms

49 – 9 = HF²

40 = HF²

Take the square root of both side

HF = √40

Finally, we shall determine FG. This can be obtained as follow:

GH = 3

HF = √40

FG =.?

FG² = GH² + HF²

FG² = 3² + (√40)²

FG² = 9 + 40

FG² = 49

Take the square root of both side

FG = √49

FG = 7

User Bisamov
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