Question

find the area of the figure below composed of a rectangle with a semicircle removed from it. Round to the nearest tenths place​

Answer 1

Area of rectangle - area of semicircle

L×B - πr square /2

Area = 124/7...

Answer 2

The area of the figure, consisting of a rectangle with a semicircle removed, is approximately
`\(17.7 \, \text{units}^2\)`, rounded to the nearest tenth.

To find the area of the figure composed of a rectangle with a semicircle removed, follow these steps:

1. Rectangle Area
`(A_{rect)`:
`\(A_{\text{rect}} = \text{length} * \text{breadth} = 6 * 4 = 24 \, \text{units}^2\)`

2. Semicircle Area (
`A_}semicircle`): The diameter of the semicircle is equal to the breadth of the rectangle (d = 4), and the radius (r) is half of the diameter (r = 2). The formula for the area of a semicircle is
`\((1)/(2) \pi r^2\).`

`\[ A_{\text{semicircle}} = (1)/(2) * \pi * (2)^2 = 2 \pi \, \text{units}^2 \]`

3. Area of the Figure (
`A_{total`): Subtract the semicircle area from the rectangle area.

`\[ A_{\text{total}} = A_{\text{rect}} - A_{\text{semicircle}} = 24 - 2 \pi \approx 17.7 \, \text{units}^2 \]`