Answer:
A trig wave with average height 0 has the form f(t)=Acos(ωt+ϕ). You could also use the sin - it doesn't matter.
A trig wave with average height b has the form f(t)=b+Acos(ωt+ϕ)
The difference between the max and min heights is 2A. In your problem 2A = 55-12 = 42 so that A = 21.5.
The average wave height is b = 12 + A = 33.5
The time period of the wave is 3, so that its frequency (waves per second) is f = 1/3. Its angular frequency ω (waves per 2π) is 2πf=2π/3.
your wave is now f(t)=33.5+21.5cos(2πt/3+ϕ)
When t = 1.1 the max height is reached so that 55=33.5+21.5cos(2π(1.1)/3+ϕ). Then 1=cos(2π(1.1)/3+ϕ) which in turn means that 2π(1.1)/3+ϕ=0 and solving gives ϕ.
Key Points. One radian is the measure of the central angle of a circle such that the length of the arc is equal to the radius. of the circle. A full revolution of a circle (360∘ ) equals 2π radians 2 π r a d i a n s . This means that 1 radian=180∘π 1 radian = 180 ∘ π
Hope it helps