Question

Please see the question and solve plz​

Answer 1

Explanation:

sin²β + sin²β×tan²β = tan²β

sin²β( 1 + tan²β ) = tan²β

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sin²β + cos²β = 1

`(sin^2\beta )/(cos^2\beta )` +
`(cos^2\beta )/(cos^2\beta )` =
`(1)/(cos^2\beta )` ⇒ tan²β + 1 = sec²β ⇔ 1 + tan²β = sec²β

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1 + tan²β =
`(1)/(cos^2 \beta )`

L.H. = sin²β (
`(1)/(cos^2 \beta )` ) = tan²β

R.H. = tan²β