Question

A car is traveling at 50 mi/h when the brakes are fully applied, producing a constant deceleration of 22 ft/s2. What is the distance covered before the car comes to a stop

Answer 1

The correct solution is "122.2211".

Step-by-step explanation:

Given:

deceleration,

a = 22 ft/sec²

Initial velocity,

`V_i=50 \ m/h`

Now,

`V_i=50 \ m/h* 5280 \ ft/m* hr/3600 \ s`

`=73.333 \ ft/sec`

Now,

Final velocity,

`V_f=0`

Initial velocity,

`V_(initial) = 73.333 \ ft/sec`

hence,

⇒
`V_f^2=V_i^2+2aD`

By putting the values, we get

`0=(73.333)^2+2*( -22) D`

`44D=(73.333)^2`

`D=((73.333)^2)/(44)`

`=122.2211`