Question

d) A product contains three lasers, and the product fails if any of the lasers fails. Assume the lasers fail independently. What should the mean life equal for 99% of the products to exceed 10000 hours before failure

Answer 1

Let the probability laser works = p

The probability that the system works =
`$P(\text{all three component works}) = p^3 $`

= 0.99

Therefore, p = 0.9967

Now for the above probability critical z = -2.72

Hence, the mean life is equal to =
`10,000 + 2.72 * 600`

=
`10,000+1632`

`=11,632`