Explanation:
a) X is a discrete uniform distribution. As the number of outcomes is only 3.
b) sum is at least 4
X ≥ 4--------
i.e (1,3) or (2,3)
probability of X ≥ 4 is 2/3
2/3= 0.667
66.7 % is the probability of the outcome to have a sum at least 4.
c) The 3 likely outcome of X
(1,2) where X ; 1+2=3
(1,3) where X ; 1+3=4
(2,3) where X ; 2+3=5
Mean = 3+4+5/ 3
Mean = 4
Feel free to ask any uncleared step