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42 votes
42 votes
Help please!! Plots of land between two roads are laid out according to the boundaries shown. The boundaries between the two roads are parallel. What is the length of Plot 3 along Cheshire Road?

Help please!! Plots of land between two roads are laid out according to the boundaries-example-1
User Kavita Patil
by
2.9k points

2 Answers

17 votes
17 votes

Answer:

46
(2)/(3) (For those with the Shelby Road Plot 3 Measurement that says 56 yards.)

Step-by-step explanation:


(40)/(48) = (x)/(56) \\\\48x = 2240\\\\x = 46.6667 \\or 46(2)/(3)

User J L
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3.0k points
24 votes
24 votes

Answer: Choice D

53 and 1/3 yards

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Work Shown:

40/48 = x/64

5/6 = x/64

5*64 = 6*x

320 = 6x

6x = 320

x = 320/6

x = 53.33333...

x = 53 + 0.3333...

x = 53 + 1/3

x = 53 and 1/3, answer is choice D

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Step-by-step explanation:

Basically because the quadrilaterals are similar, this means the sides are proportional to one another. This allows us to set up the equation at the very top. In step 3, I cross multiplied. Then later on, I divided both sides by 6.

Keep in mind that the similar figures are because of the parallel lines. If the lines weren't parallel, then the figures may not be similar.

User Neotam
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2.9k points