Answer:
We fail to reject the null and conclude thattherw is no difference in population means.
Explanation:
Before After
5.6 6.4
1.3 1.5
4.7 4.6
3.8 4.3
2.4 2.1
5.5 6.0
5.1 5.2
4.6 4.5
3.7 4.5
H0 : There is no difference in population
H1 : There population are not all equal
Difference, d = (Before - After)
d = -0.8, -0.2, 0.1, -0.5, 0.3, -0.5, -0.1, 0.1, -0.8
The test statistic :
T = dbar / (Sd/√n)
dbar = Σx / n = - 2.4 / 9 = 0.2666
Standard deviation of difference Sd; [√Σ(d - dbar)² / n-1]
Sd = 0.403 (using calculator)
Hence,
T = dbar / (Sd/√n)
-0.266 / (0.403/√9)
-0.266 / 0.1343333
= - 1.980
The Pvalue ;
df = n - 1 ; 9 - 1 = 8
Pvalue(-1.980, 8) = 0.083
α = 0.05
Since Pvalue > α; We fail to reject the null and conclude thattherw is no difference in population means.