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Could someone help me arrange these pairs of points in increasing order of the slopes of the lines joining them. (15, 30) and (20, 40) (12, 32) and (18, 48) (27, 12) and (72, 32) (45, 15) and (60, 20) (27, 2) and (243, 18) (18, 63) and (24, 84) (63, 9) and (84, 12).

User Luigi Saggese
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2 Answers

16 votes
16 votes

Answer:

From least to greatest slope, the pair of points are:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

Explanation:

User Pete McKinney
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3.2k points
20 votes
20 votes

Answer:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

Explanation:

Required

Arrange in increasing order of slope

Slope (m) is calculated using:


m = (y_2 -y_1)/(x_2 - x_1)

So, we have:

(a) (15, 30) and (20, 40)


m = (40 -30)/(20- 15)


m = (10)/(5)


m =2.00

(b) (12, 32) and (18, 48)


m = (48 -32)/(18- 12)


m = (16)/(6)


m = 2.67

(c) (27, 12) and (72, 32)


m = (32-12)/(72- 27)


m = (20)/(45)


m = 0.44

(d) (45, 15) and (60, 20)


m = (20-15)/(60- 45)


m = (5)/(15)


m = 0.33

(e) (27, 2) and (243, 18)


m = (18-2)/(243- 27)


m = (16)/(216)


m = 0.07

(f) (18, 63) and (24, 84)


m = (84-63)/(24- 18)


m = (21)/(6)


m = 3.50

(g) (63, 9) and (84, 12)


m = (12 -9)/(84- 63)


m = (3)/(21)


m = 0.14

From least to greatest slope, the pair of points are:

(e) (27, 2) and (243, 18)

(g) (63, 9) and (84, 12)

(d) (45, 15) and (60, 20)

(c) (27, 12) and (72, 32)

(a) (15, 30) and (20, 40)

(b) (12, 32) and (18, 48)

(f) (18, 63) and (24, 84)

User Rahul Rastogi
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2.9k points