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Geometry!!!!!!!!! helppp

Geometry!!!!!!!!! helppp-example-1
User Kaliq
by
2.1k points

1 Answer

13 votes
13 votes

Answer:

Solution given:

Centre (h,k)=(-6,-2)

end points are:

A
\bold{(x_(1),y_(1))=(-1,-9) \:and \:B(x_(2),y_(2))=(-11,5)}

Now

distance between A to M is:

AM=
\sqrt{(h-x_(1))²+(k-y_(1))²}

AM=
√((-6+1)²+(-2+9)²)=8.6units

again

distance between B to M is:

BM=
\sqrt{(h-x_(2))²+(k-y_(2))²}

BM=
√((-6+11)²+(-2-5)²)=8.6units

again

Since AM=BM=8.6units

so

M is the centre of the circle.:Yes

User Husky
by
3.0k points