Question

A gas bottle contains 0.650 mol of gas at 730. mmHg pressure. If the final pressure is 1.15 atm, how many moles of gas were added to the bottle

Answer 1

Answer: There are 0.779 moles of gas were added to the bottle.

Step-by-step explanation:

Given:
`n_(1)` = 0.650 mol,
`P_(1)` = 730 mm Hg (1 mm Hg = 0.00131579 atm) = 0.96 atm

`n_(2)` = ?,
`P_(2)` = 1.15 atm

Formula used is as follows.

`(P_(1))/(n_(1)) = (P_(2))/(n_(2))`

Substitute the values into above formula as follows.

`(P_(1))/(n_(1)) = (P_(2))/(n_(2))\\(0.96 atm)/(0.650 mol) = (1.15 atm)/(n_(2))\\n_(2) = 0.779 mol`

Thus, we can conclude that there are 0.779 moles of gas were added to the bottle.