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A 10.0 L balloon contains helium gas at a pressure of 655 mmHg. What is the final pressure, in millimeters of mercury, if the final volume is 13.8 L? Please show your work in order to receive credit.

User Bera
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1 Answer

16 votes
16 votes

Answer:

474. 64 mm Hg

Step-by-step explanation:

  • P1 = 655 mm Hg
  • V1 = 10 L

  • P2 = ?
  • V2 = 13. 8 L

using Boyle's Law that is

P1. V1 = P2. V2

655 × 10 = P2 × 13. 8


P2 = (655 * 10)/(13.8)

P2 = 474. 64 mm Hg

User Maydin
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