Question

What’s and equation for a line that passes through (6,3) and (-6,6)?

Answer 1

x + 5y -18=0

Explanation:

Two points are given to us and we need to find the equation of the line. The given points are (6,3) and (-6,6) . Firstly let's find out the slope of the line .

Finding slope :-

`\implies Slope = ( y_2-y_1)/(x_2-x_1) \\\\\implies Slope =( 3-6)/(6+6) \\\\\sf\implies Slope =( -3)/(12) \\\\\sf\implies Slope = (-1)/(4)`

Using point slope form :-

`\implies y - y_1 = m( x - x_1 ) \\\\\sf\implies y - 3 = (-1)/(4)( x - 6)\\\\\sf\implies 4y - 12 = 6 - x \\\\\sf\implies x + 4y -12-6=0 \\\\\sf\implies\underline {\underline{ x + 5y -18=0}}`