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41 votes
What is the [h+] if the ph of a solution is 11.13

pls help

User Onsy
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1 Answer

9 votes
9 votes

Step-by-step explanation:


[{H}^( + )] = {10}^( - pH)


= {10}^( - 11.13)


= {10}^( (- 11 - 0.13))


= {10}^( - 0.13) * {10}^( - 11)


= 0.741 * {10}^( - 11) (mol)/(litre)

HOPE IT HELPS YOU

User Olly Hodgson
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