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15 votes
2x - 3y = 9
-5x – 3y = 30
Elimination method

User Stano
by
3.3k points

1 Answer

6 votes

Answer:

The solution to the system of the equations be:

  • (x, y) = (-3, -5)

Explanation:

Given the system of equations


2x - 3y = 9


-5x - 3y = 30

Solving the system of equations using the elimination method

Multiply
2x-3y=9 by 5:
10x-15y=45

Multiply
-5x-3y=30 by 2:
-10x-6y=60


\begin{bmatrix}10x-15y=45\\ -10x-6y=60\end{bmatrix}

adding the equations


-10x-6y=60


+


\underline{10x-15y=45}


-21y=105

now solving -21y = 105 for y


-21y=105

Divide both sides by -21


(-21y)/(-21)=(105)/(-21)

Simplify


y=-5

For 10x - 15y = 45 plug in y = -5


10x-15\left(-5\right)=45

Apply the rule -a(-a) = a


10x+15\cdot \:5=45


10x+75=45

Subtract 75 from both sides


10x+75-75=45-75

Simplify


10x=-30

Divide both sides by 10


(10x)/(10)=(-30)/(10)

Simplify


x=-3

Therefore, the solution to the system of the equations be:

  • (x, y) = (-3, -5)

The graph of the solution to the system of equations is also attached below.

2x - 3y = 9 -5x – 3y = 30 Elimination method-example-1
User Mohammed Nagoor
by
3.4k points