Answer:
The correct answer is - 3 (two codons of 507th that are U, C, and the first nucleotide of 508th codon U).
Step-by-step explanation:
Each amino acid is coded by a three-nucleotide base long codon. So in the case of the F508del variant, there is a deletion of three nucleotides that is encoded for phenylalanine amino acid.
In this isoleucine is encoded by 507th codon that is AUG and 508th codon is UUU codes for Isoleucine.
In this case, two codons of 507th are U, C, and the first nucleotide of 508th codon U. So overall three nucleotides are deleted in the F508del variant..