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13 votes
13 votes
Select the two values of x that are roots of this equation.

x² + 3x-6=0
A. X=
-3+ /33
2
B. x=-3-83
c. x. -3-15
D. x. -3*4/15
please help

User Ritesh Khatri
by
2.8k points

1 Answer

21 votes
21 votes

Answer:


x1 = ( - 3 - √(33) )/(2) \\ x2 = ( - 3 + √(33) )/(2)

Explanation:


x = \frac{ - b + - \sqrt{ {b}^(2) - 4ac} }{2a} \\ = ( - 3 + - √(9 + 24) )/(2) \\ x1 = ( - 3 - √(33) )/(2) \\ x2 = ( - 3 + √(33) )/(2)

User Bill Ingram
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