Question

You are on an airplane that is landing. The plane in front of your plane blows a tire. The pilot of your plane is advised to abort the landing, so he pulls up, moving in a semicircular upward-bending path. The path has a radius of 450 m with a radial acceleration of 17 m/s^2.

Required:
What is the plane's speed?

Answer 1

v = 87.46 m/s

Step-by-step explanation:

The radial acceleration is the centripetal acceleration, whose formula is given as:

`a_c = (v^2)/(r)`

where,

`a_c` = centripetal acceleration = 17 m/s²

v = planes's speed = ?

r = radius of path = 450 m

Therefore,

`17\ m/s^2 = (v^2)/(450\ m)\\\\v^2 = (17\ m/s^2)(450\ m)\\\\v = √(7650\ m^2/s^2)`

v = 87.46 m/s