Question

Helpppppppppp anyone know algebra?

Answer 1

5x/7y^3

Explanation:

Something to the power of -1/2 is saying 1 over square-root of that something. Let's pretend x is that something. If we have something like this
`x^{-(1)/(2) }`, then it can be written like this:
`(1)/(√(x))`.

In our problem, we have the chunk to the -1/2 power. So the reciprocal of the chunk would become
`\sqrt{(25x^(2) )/(49y^(6))`

It's easy to solve now. The square root of the numerator becomes 5x and the denominator becomes 7y^3. The simplified version is
`\frac{5x}{7y^\power{3}}`