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If 3(d+1)=4(d–2),
then what is the value of 5(d–2)?

User Mevrael
by
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1 Answer

7 votes

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Answer:

45

Explanation:

Solving for d, we find ...

3(d +1) = 4(d -2)

3d +3 = 4d -8 . . . . . . eliminate parentheses

11 = d . . . . . . . . . . . . subtract 3d-8

Then the value of 5(d-2) is ...

5(11 -2) = 5(9) = 45

_____

The graphical solution gives both the value of "d" and the value of 4(d-2). To get 5(d-2), we only need to add d-2 to the value of 4(d-2).

5(d-2) = (11 -2) +36 = 45

If 3(d+1)=4(d–2), then what is the value of 5(d–2)?-example-1
User J Miller
by
4.4k points