Question

Given that g(x) = 2x ^ 2 - 2x + 8 , find each of the following. a) g(0) b) g(- 2) C) g(3) d) g(- x) e) g(1 - t)

Answer 1

a) 8

b) 20

c) 20

Explanation:

a) Insert X=0 from g(0) to the equation: 2(0) power of 2 - 2x0 +8.

b) Insert X=(-2) from g(-2) to the equation: 2(-2) power of 2 - 2x(-2) +8.

c) Insert X=3 from g(3) to the question 2(3) power of 2 - 2x3 +8.

Answer 2

`g(-2)=20`

Explanation:

Given
`g(x)=2x^2-2x+8`, substitute what is in the parentheses for
`x` to find an output.

For
`g(-2)`, the term
`-2` is in the parentheses. Thus, substitute
`x=-2` into
`2x^2-2x+8` to find
`g(-2)`:

`g(-2)=2(-2)^2-2(-2)+8,\\g(-2)=2\cdot 4+4+8,\\g(-2)=8+4+8,\\g(-2)=\boxed{20}`