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GET 95 POINTS Let f(x) = 1/x and g(x)=x² + 6x. What

two numbers are not in the domain of fᵒg?
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GET 95 POINTS Let f(x) = 1/x and g(x)=x² + 6x. What two numbers are not in the domain-example-1
User KyriakosSt
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1 Answer

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19 votes

Answer:

hey there hope this answer helps you out

Explanation:

we have two functions f(x) and g(x) such that


f(x) = (1)/(x)

and


g(x) = {x}^(2) + 6x

solving for f ° g, we'll substitute the x in f(x) by the value of g(x)


fog = (1)/(g(x))


fog \: = \frac{1}{ {x}^(2) + 6x }

taking x common in denominator


fog = (1)/(x(x + 6))

for a function to exist it should not have 0 in its denominator

checking the values of x for which the denominator of f ° g becomes 0 :-

  • x = 0 and
  • x = -6

so the function doesn't exist at values x = 0, -6

So, 0, -6 cannot be in the domain of f°g

User Carter Shaw
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