Answer:
Explanation:
This appears to be an SSA application of solving the triangle
We have 2 sides, so we will use the law of cosines
The law of cosines defines for a triangle ABC with side a/b/c with corresponding angles A/B/C
a^2 = b^2+c^2 - 2*b*c * (cos A)
this applies to the other 2 sides
first using the pythagorean theorem we find that BC = sqrt(55)
then we substitute all 3 sides into our equation to find angle A
55 = 64 + 9 - 2*8*3* (cos A)
18 = 2*8*3(cos A)
3/8 = (cos A)
and angle A is approximately 68 degrees
Please check if I'm correct