Question

Plis help me it’s for today

Answer 1

Following are the solution to the given points:

Explanation:

For question 1:

`\to 3^(-4)= (1)/(3^4)=(1)/(81)=0.0123456789`

For question 2:

`\to (-2)^(3)\cdot(-2)^(4)\cdot(-2)^(-1)=-8\cdot-16\cdot -(1)/(2)= 128\cdot -(1)/(2)=-64`

For question 3:

`\to 7^(-4) / 7^(-2)= (1)/(7^(4)) / (1)/(7^(2))=(1)/(7^(4)) * (7^(2))/(1)=(1)/(7^(2)) =(1)/(49) =0.0204081633`

For question 4:

`\to [(-3)^(2)]^3= (-3)^(2\cdot 3)= (-3)^(6)=729`

For question 5:

`\to [5 \cdot (-3)]^(2)= 25 \cdot 9=225`

For question 6:

`\to [(10 / 5)]^(3)= [((10)/(5))]^(3)=[2]^(3)=8`

For question 7:

`\to 10^6 \cdot 10^(-4) \cdot 10^2= 10^6 \cdot (1)/(10^(4)) \cdot 10^2= 10^2 \cdot 10^2=10^4=10,000`

For question 8:

`\to (-4)^(-5)=(1)/((-4)^(5))=- (1)/(1,024)=-0.0009765625`

For question 9:

`\to (2^3)/(2^4)= (8)/(16)=(1)/(2)=0.5`

For question 10:

`\to (-6)^3 \cdot (-6)^5 \cdot (-6)^(-5)= (-6)^3 \cdot (-6)^5 \cdot (1)/((-6)^(5))= (-6)^3 =-216`