Question

Use the ideal gas law, PV=nRT to solve. R=0.0821

If I have 15 moles of gas at a temperature of 299K and a volume of 92L, what is the pressure of the gas?

Answer 1

According to the ideal gas law equation,

PV = nRT (here, P = 5.5 atm, V = 10L, T = 298K, R = 0.0821 atmL/mol K)

or, n = RT/PV = (0.0821 X 298)/(5.5 X 10) = 0.44 moles of He gas

Step-by-step explanation:

Answer 2

The pressure of the gas=4.002 atm

Step-by-step explanation:

We are given that

R=0.0821

Number of moles, n=15

Temperature, T=299 K

Volume of gas, V=92 L

We have to find the pressure of the gas.

`PV=nRT`

Substitute the values

`P* 92=15* 0.0821* 299`

`P=(15* 0.0821* 299)/(92)`

`P=4.002 atm`

Hence, the pressure of the gas=4.002 atm