Question

At room temperature and pressure 14.2 g of chlorine will occupy what volume of gas

Answer 1

9.6
`dm^(3)`

Step-by-step explanation:

Volume at room temperature & pressure = no. of moles × 24
`dm^(3)`

No. of moles = mass ÷ mass of 1 mole

= 14.2 ÷ 35.5

= 0.4 moles

Volume = 0.4 × 24 = 9.6
`dm^(3)`