Question

A 55 g soapstone cube--a whisky stone--is used to chill a glass of whisky. Soapstone has a density of 3000 kg/m3, whisky a density of 940 kg/m3. What is the approximate normal force of the bottom of the glass on a single stone?

Answer 1

`N=0.37N`

Step-by-step explanation:

Mass
`m=55g=>0.055kg`

Soapstone Density
`\rho_s=3000kg/m^2`

Whisky Density
`\rho_w=940kg/m^2`

Generally the equation for Force is mathematically given by

`F=U+N`

Therefore

`N=m*g-((m)/(\rho_s))*\rho_w*g`

`N=0.055*9.81 - {((0.055)/(3000))*940*9.81}`

`N=0.37N`