Question

This question is divided into two parts. This is part (a) of the question. A proton accelerates from rest in a uniform electric field of 580 N/C. At some later time, its speed is 1.00 x 106 m/s. (a) Find the magnitude of the acceleration of the proton. (Mass of the proton is 1.67 x 10-27 kg and charge is 1.60 x 10-19 C) (in the following options 10^10 m/s^2 is 1010 m/s2)

Answer 1

The acceleration of proton is 5.56 x 10^10 m/s^2 .

Step-by-step explanation:

initial velocity, u = 0

Electric field, E = 580 N/C

final speed, v = 10^6 m/s

(a) Let the acceleration is a.

According to the Newton's second law

F = m a = q E

where, q is the charge of proton and m is the mass.

`a= (q E)/(m)\\\\a = (1.6*10^(-19)* 580)/(1.67* 10^(-27))\\\\a= 5.56* 10^(10) m/s^2`