Question

( t^15/27x^9 ) ^-2/3

Please solve this
it is fraction with a negative fraction exponent

Answer 1

Explanation:

Exponent laws:

`(a^(m))^(n)=a^(m*n)\\\\a^(-m)=(1)/(a^(m))`

`(t^{(15)/(27)}x^(9)})^{(-2)/(3)}= \ t^{(15)/(27)*(-2)/(3)}*x^{9*(-2)/(3)}\\\\\\= t^{(5)/(9)*(-2)/(3)}*x^(3*-2)\\\\=t^{(-10)/(27)}x^(-6)\\\\=\frac{1}{t^{(10)/(27)}x^(6)}`