Question

Solve the following simultaneous linear equations by the substitution method.

3x + 4y = 1
2x + 3y = 1​

Answer 1

`\displaystyle\bf \left \{ {{3x+4y=1} \atop {2x+3y=1}} \right. => \left \{ {{x=(1-4y)/(3) } \atop {2x+3y=1}} \right. => \\\\\\2\cdot(1-4y)/(3) +3y=1\: |*3\\\\2-8y+9y=3\\\\y+2=3\\\\y=1 \;;\:x=(1-4y):3=-1\\\\\\Answer: (-1;1)`