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A child who is swimming toward shore at 0.78 m/s sees shark and picks up his speed to 1.89 m/s. He covers 17.5 m until he lands on shore. What was his acceleration?
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3 votes
A child who is swimming toward shore at 0.78 m/s sees shark and picks up his speed

to 1.89 m/s. He covers 17.5 m until he lands on shore. What was his acceleration?

User Mjsr
by
2.5k points

1 Answer

11 votes
11 votes

Answer:

0.085m/s²

Step-by-step explanation:

Use v²=v0²+2a(d)

solve for a

v²-v0²/2d=a

Plug in givens

1.89²-0.78²/2*17.5=a

Plug into calculator

a=0.085m/s²

User Jeffrey Sarnoff
by
2.8k points
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