Question

What is the equation in slope-intercept form of the line that passes through the points(-4,2) and (12,6)?

Answer 1

y=1/4x+3

Explanation:

m=(y2-y1)/(x2-x1)

m=(6-2)/(12-(-4))=4/(12+4)=4/16=1/4

y-y1=m(x-x1)

y-2=1/4(x-(-4))

y-2=1/4(x+4)

y=1/4x+4/4+2

y=1/4x+1+2

y=1/4x+3