Question

A cylinder contains 26.5 L of oxygen gas at a pressure of 1.7 atm and a temperature of 280 K. How much gas (in moles) is in the cylinder?

Answer 1

The appropriate answer is "1.96 mol".

Step-by-step explanation:

The given values are:

Volume,

V = 26.5 L

Pressure,

P = 1.7 atm

Temperature,

T = 280 K

Now,

The number of moles (n) will be:

=
`(PV)/(RT)`

By substituting the values, we get

=
`(1.7* 26.5)/(0.0821* 280)`

=
`(45.05)/(22.988)`

=
`1.96 \ mol`